A. 495. In the acute triangle ABC we have BAC=. The point D lies in the interior of the triangle, on the bisector of BAC, and points E and F lie on the sides AB and BC, respectively, such that BDC=2, AED=90o+, and BEF=EBD. Determine the ratio BF:FC.
Deadline expired on 11 January 2010.
Solution. Let G be the reflection of E through the bisector AD. Reflect point D through the lines AB and AC; denote the reflections by U and V, respectively. We have UE=DE=DG=VG.
From the deltoid AEDG we obtain and .
Moreover, and .
Since BEU=AEG and CGV=AGE, the ponts U, E, G and V are collinear.
Leet BEF=BDE=EBU=x and CGF=CDG=GCV=z. From the quadrilateral ABDC and the triangle ABC, we have x+y=360o--(360o-2)= and
Therefore, the lines BU and CV are parallel. Due to EBU=VEF, also the line EF is parallel with them.