Problem B. 3893. (March 2006)
B. 3893. Solve the equation
(x2+y2)3=(x3-y3)2
on the set of real numbers.
(3 pont)
Deadline expired on April 18, 2006.
Sorry, the solution is available only in Hungarian. Google translation
Megoldás: A zárójeleket kibontva, rendezés után a 3x4y2+3x2y4+2x3y3=0 egyenletre jutunk, vagyis
Ez pedig pontosan akkor teljesül, ha x és y közül legalább az egyik 0.
Statistics:
204 students sent a solution. 3 points: 154 students. 2 points: 19 students. 1 point: 28 students. 0 point: 2 students. Unfair, not evaluated: 1 solutions.
Problems in Mathematics of KöMaL, March 2006