KöMaL - Mathematical and Physical Journal for Secondary Schools
Hungarian version Information Contest Journal Articles News
Entry form to the contest
Problems and solutions
Results of the competition
Problems of the previous years



Order KöMaL!

Competitions Portal

P. 4315. Two balls of masses m1=0.173 kg and m2=0.2 kg are moving and the direction of their motion is perpendiculer to each other. Their speeds are v1=10 m/s and v2=5 m/s, respectively. After the collision the ball of mass m1 stops. What will the speed of the ball of mass m2 be after the collision?

(4 points)

Deadline expired on 10 March 2011.

Google Translation (Sorry, the solution is published in Hungarian only.)

Megolds. Az tkzs eltt a kt goly egyttes lendlete a merleges haladsi irny miatt &tex;\displaystyle \sqrt{m_1^2v_1^2+m_2^2v_2^2}&xet;. Az tkzs utn a teljes lendletet a 2-es goly viszi el, ezrt ennek sebessge &tex;\displaystyle v_2'=\sqrt{\left( \frac{m_1}{m_2} \right)^2v_1^2+v_2^2}\approx 10&xet; m/s.

Statistics on problem P. 4315.
171 students sent a solution.
4 points:106 students.
3 points:24 students.
2 points:10 students.
1 point:26 students.
0 point:1 student.
Unfair, not evaluated:4 solutions.

  • Problems in Physics of KMaL, February 2011

  • Our web pages are supported by:   Ericsson   Google   Cognex   Emberi ErőforrĂĄs TĂĄmogatĂĄskezelő   Emberi ErőforrĂĄsok MinisztĂŠriuma  
    OktatĂĄskutatĂł ĂŠs Fejlesztő IntĂŠzet   Nemzeti TehetsĂŠg Program     Nemzeti
KulturĂĄlis Alap   ELTE   Morgan Stanley