Problem P. 4315.

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P. 4315. Two balls of masses m₁=0.173 kg and m₂=0.2 kg are moving and the direction of their motion is perpendiculer to each other. Their speeds are v₁=10 m/s and v₂=5 m/s, respectively. After the collision the ball of mass m₁ stops. What will the speed of the ball of mass m₂ be after the collision?

(4 points)

Deadline expired.

Sorry, the solution is published in Hungarian only.

Az ütközés előtt a két golyó együttes lendülete a merőleges haladási irány miatt $\sqrt{m_1^2v_1^2+m_2^2v_2^2}$ . Az ütközés után a teljes lendületet a 2-es golyó viszi el, ezért ennek sebessége $v_2'=\sqrt{\left( \frac{m_1}{m_2} \right)^2v_1^2+v_2^2}\approx 10$ m/s.

Statistics on problem P. 4315.

171 students sent a solution.

4 points: 106 students.

3 points: 24 students.

2 points: 10 students.

1 point: 26 students.

0 point: 1 student.

Unfair, not evaluated: 4 solutions.

Problems in Physics of KöMaL, February 2011

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