Problem P. 4509. (February 2013)
P. 4509. How long is the shadow of a 1 m long rod which is fixed perpendicularly to the ground at the equator
a) at noon, on the 21st of March;
b) 2 hours later after noon on the 21st of March?
(3 pont)
Deadline expired on March 11, 2013.
Sorry, the solution is available only in Hungarian. Google translation
Megoldásvázlat. \(\displaystyle a)\) Nincs árnyéka a botnak.
\(\displaystyle b)\) \(\displaystyle \frac{1}{\sqrt{3}}\cdot1~{\rm m} = \tg 30^\circ\cdot1~{\rm m}\approx 58~\rm cm.\)
Statistics:
104 students sent a solution.  
3 points:  65 students. 
2 points:  29 students. 
1 point:  10 students. 
