Problem P. 3926. (November 2006)

P. 3926. The two ends of a rubber string of negligible mass are fixed at the same height, such that the string is un-stretched. A small object is attached to the string in its midpoint, thus the angle of depression of the string is $\alpha$ =30^o. Then the small object is charged and vertical electric field is applied. Initially the depression angle of the string increases to $\alpha$ ₁=45^o, then the electric field is changed and the depression angle increases to $\alpha$ ₂=60^o. By what factor is the electric field in the second case more than that of in the first case?

(4 pont)

Deadline expired on December 11, 2006.

Statistics:

146 students sent a solution.

4 points: 89 students.

3 points: 22 students.

2 points: 23 students.

1 point: 6 students.

0 point: 4 students.

Unfair, not evaluated: 2 solutionss.

Problems in Physics of KöMaL, November 2006

146 students sent a solution.
4 points:	89 students.
3 points:	22 students.
2 points:	23 students.
1 point:	6 students.
0 point:	4 students.
Unfair, not evaluated:	2 solutionss.

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