Problem P. 4541. (May 2013)
P. 4541. How long is the shadow of a 1 m long rod, which is fixed perpendicularly to the ground at the equator,
a) at noon, on the 21-st of June;
b) 2 hours later after noon on the 21-st of June?
(5 pont)
Deadline expired on June 10, 2013.
Sorry, the solution is available only in Hungarian. Google translation
Megoldásvázlat. \(\displaystyle a)\) \(\displaystyle h_1=\tg 23{,}45^\circ=0{,}43~\rm m.\)
\(\displaystyle b)\) \(\displaystyle h_2=\sqrt{{\cos^{-2} 23{,}45^\circ\cdot \cos^{-2} 30^\circ}-1 }=0{,}76~\rm m.\)
Statistics:
65 students sent a solution. 5 points: Bingler Arnold, Fehér Zsombor, Fekete Panna, Janzer Barnabás, Juhász Péter, Kollarics Sándor, Medek Ákos, Papp Roland, Reitz Angéla, Sal Kristóf, Szabó 928 Attila, Sztilkovics Milán. 4 points: Alabér Ádám, Mezősi Máté. 3 points: 19 students. 2 points: 21 students. 1 point: 2 students. 0 point: 9 students.
Problems in Physics of KöMaL, May 2013