A. 559. The incircle of triangle ABC is k. The circle kA touches k and the segments AB and AC at at A', AB and AC respectively. The circles kB, kC and the points B', C' are defined analogously. The second intersection point of the circles A'B'AB and A'C'AC, other than A', is K. The line A'K meets k at R, other than A'. Prove that R lies on the radical axis of the circles kB and kC.
(Kolmogorov's Cup, 2011; a problem by F. Ivlev)
(5 points)
Statistics
B. 4440. On a winter's day, an absent minded mathematician went on a walk with his old poodle along a long straight alley. He was so absorbed in his thoughts that when he finally thought of his dog, he had to realize that it was not near him. In the snowfall, he did not see further than 5 metres. He did not see the dog in front of him, he did not see it behind either, and he did not know which direction it had gone. After a little thinking, he went to look for his poodle. The old poodle can only walk half as fast as its master. The mathematician chose a searching strategy, such that the following condition should hold for the smallest possible value of the constant c: if the dog is at a distance x from him then he needs to cover a distance of at most cx to find it. What is this smallest value of c?
(5 points)
Solution (in Hungarian)
K. 335. A peculiar calculator only has four buttons on it:
(eight plus root seven),
(addition),
(reciprocal) and
(equals) (see the figure).

The calculator always carries out the operations with exact values, and it can also store the current value as a constant if the
button is pressed twice. That is, in subsequent calculations whenever the
button is pressed, the number is incremented by that value any number of times. (E.g. if the buttons
are pressed, it will display
). Prove that the result of the following sequence of operations is 1:
...
(56 times)
...
(15 times)
(6 points)
Solution (in Hungarian)